(3x+5)(2x^2-7x+3)=0

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Solution for (3x+5)(2x^2-7x+3)=0 equation:


Simplifying
(3x + 5)(2x2 + -7x + 3) = 0

Reorder the terms:
(5 + 3x)(2x2 + -7x + 3) = 0

Reorder the terms:
(5 + 3x)(3 + -7x + 2x2) = 0

Multiply (5 + 3x) * (3 + -7x + 2x2)
(5(3 + -7x + 2x2) + 3x * (3 + -7x + 2x2)) = 0
((3 * 5 + -7x * 5 + 2x2 * 5) + 3x * (3 + -7x + 2x2)) = 0
((15 + -35x + 10x2) + 3x * (3 + -7x + 2x2)) = 0
(15 + -35x + 10x2 + (3 * 3x + -7x * 3x + 2x2 * 3x)) = 0
(15 + -35x + 10x2 + (9x + -21x2 + 6x3)) = 0

Reorder the terms:
(15 + -35x + 9x + 10x2 + -21x2 + 6x3) = 0

Combine like terms: -35x + 9x = -26x
(15 + -26x + 10x2 + -21x2 + 6x3) = 0

Combine like terms: 10x2 + -21x2 = -11x2
(15 + -26x + -11x2 + 6x3) = 0

Solving
15 + -26x + -11x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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